-3x^2+x=-8

Solution for -3x^2+x=-8 equation:

-3x^2+x=-8

We move all terms to the left:

-3x^2+x-(-8)=0

We add all the numbers together, and all the variables

-3x^2+x+8=0

a = -3; b = 1; c = +8;
Δ = b2-4ac
Δ = 12-4·(-3)·8
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{97}}{2*-3}=\frac{-1-\sqrt{97}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{97}}{2*-3}=\frac{-1+\sqrt{97}}{-6}
$